1.5x^2+x-1=0

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Solution for 1.5x^2+x-1=0 equation:



1.5x^2+x-1=0
a = 1.5; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·1.5·(-1)
Δ = 7
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{7}}{2*1.5}=\frac{-1-\sqrt{7}}{3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{7}}{2*1.5}=\frac{-1+\sqrt{7}}{3} $

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